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qcm 25 session 2 chimie cinétique


Go to solution Solved by saucebiggy,

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  • Solution

Salut, pour la E, l'ordre de réaction = 1 donc on peut utiliser la formule ln(Ao/A) = k.t avec Ao = 1,6 M et A = 10% de Ao = 0,16 M 

donc t = ln(1,6/0,16) / k donc t = ln(10)/k 

ITEM VRAI 

Par contre je ne sais pas trop pour la D, peut-être que @Le_Polâuné pourrait t'éclairer...

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