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td optique 3 exercice 3


juliette5
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  • Ancien du Bureau
  • Solution

Re :'))

 

1/SA' + 1/SA = 2/SC

<=> 1/SA' = 2/SC - 1/SA

<=> 1/SA' = 2SA - SC / SA.SC

(on applique la fonction 1/x -->)

<=> SA' = SA.SC/2SA-SC

Et on sait que SC=R donc

<=> SA' = SA.R/2SA-R 

 

C'est bon ? 

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  • Ancien du Bureau
il y a 1 minute, evapochat a dit :

bonjour, c'est surement tout bête mais je n'arrive pas a comprendre cette étape....

Celle la 

Il y a 9 heures, DuTACKauTac a dit :

<=> 1/SA' = 2/SC - 1/SA

<=> 1/SA' = 2SA - SC / SA.SC

 

Ou celle la 

Il y a 9 heures, DuTACKauTac a dit :

<=> 1/SA' = 2SA - SC / SA.SC

(on applique la fonction 1/x -->)

<=> SA' = SA.SC/2SA-SC

??

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  • Ancien du Bureau
il y a 1 minute, evapochat a dit :

celle la 

Quand tu as 1/4 - 2/3 

Tu vas faire 3-8/12 

Genre tu multiplie les numérateurs par le dénominateur de l'autre fraction, et les dénominateurs entre eux 

C'est bon pour toi ?

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