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mécanique des fluides


unelas
Go to solution Solved by EniramJ,

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Bonjour, j'aurais besoin d'aide pour ce qcm ☺️ (CCB rangueil 2017)

 

je ne comprends comment à l'item C on trouve 4,5 car moi je trouve 1,5 en appliquant la formule V2 = (A1xV1)/A2

et ensuite, comment fait on pour calculer la pression à l'item D?

merci! 

 

https://zupimages.net/viewer.php?id=20/49/nsnj.png

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  • Solution

Salut ! 

Pour le C tu utilises la formule : v*S = constante

Donc on a v1*S1 = v2*S2

0,5*6²*π = v2*2²*π

18 = v2*4 = 4,5 

 

Pour le D tu utilises la formule : p + hρg +1/2ρv² = constante

p1 + hρg +1/2ρv²1 = p2 + hρg +1/2ρv²2 

p2 = -1/2ρv²2 + 1/2ρv²1 + p1

p2 = 1/2ρ(v²1 - v²2) + p1

p2 = 1/2*103(0,5²-4,5²) + 105

p2 = -104 + 105

p2 = 0,9* 105

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