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probleme de periode

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saluut, alors tu dois utiliser la formule A = A0 x (1- lambda x t) en sachant que lambda = ln 2 / T avec ln2 = 0.7

donc ici tu as t = 10j et T= 372j d'où A = A0 x (1 - 0.7 x 10/372) que tu peux arrondir à A = A0 x (1 - 0.7 x 10/400) = A0 x (1 - 0.7 x 0.025) = A0 x 0.98 

donc l'activité de la source est bien multipliée par un facteur 0.981 tous les 10j 😉 

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