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Purpan 2016


Go to solution Solved by SeverusRogue,

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Salut,

N'y aurait il pas à l'item C un probleme de signe ?  (l'item est compter juste)

 

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J'ai surement tort dans mes calculs mais j'ai pas su me corriger 😕 :

On a Kd = 10^-5 soit Ka = 10^5

or pKa = -log Ka = -5

vu que que c'est un monoacide faible on applique la formule : ph = 1/2(pka - log m) avec m = 10^-2

on a -log 10^-2 = 2

conclusion  ph = 1/2 (-5+2) = -3,5                        rip

Edited by STABILh2o
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Merci !!

Autre chose stp, Ka en temps que cte d'equlibre d'association, ou est ce qu'elle intervient ?

 

Edited by STABILh2o
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