JJA Posted January 3, 2020 Share Posted January 3, 2020 hey, c'est pour savoir comment on arrive à trouver le facteur 1250 dans l'item E, de ce CQM. Merci d'avance Quote Link to comment Share on other sites More sharing options...
Solution Le_Chapelier_Fou Posted January 3, 2020 Solution Share Posted January 3, 2020 (edited) Hey ! L'appromixation affine ça correspond à la partie affine du DL1 c'est à dire g(t) + t*g'(t) : g(0) = 100/2 + 50 g'(t) = 100*50/(1+e^-50t)² g'(0) = 5000/4 = 1250 Soit g(t) + t*g'(t) = 50 + 1250t, pour t = 0 Edited January 3, 2020 by Le_Chapelier_Fou Quote Link to comment Share on other sites More sharing options...
JJA Posted January 4, 2020 Author Share Posted January 4, 2020 Niquel merci Quote Link to comment Share on other sites More sharing options...
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