JJA Posted January 3, 2020 Posted January 3, 2020 hey, c'est pour savoir comment on arrive à trouver le facteur 1250 dans l'item E, de ce CQM. Merci d'avance Quote
Solution Le_Chapelier_Fou Posted January 3, 2020 Solution Posted January 3, 2020 (edited) Hey ! L'appromixation affine ça correspond à la partie affine du DL1 c'est à dire g(t) + t*g'(t) : g(0) = 100/2 + 50 g'(t) = 100*50/(1+e^-50t)² g'(0) = 5000/4 = 1250 Soit g(t) + t*g'(t) = 50 + 1250t, pour t = 0 Edited January 3, 2020 by Le_Chapelier_Fou Quote
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