Ancien Responsable Matière Noel_Flantier Posted December 17, 2019 Ancien Responsable Matière Share Posted December 17, 2019 (edited) Bonjour, Sur le qcm ci dessous, je ne comprends pas pourquoi l'item C est vrai La molécule M augmente le Vmax donc se comporte-t-elle pas plutot comme un "activateur non compétitif" ? Un grand merci d'avance ! Edited July 22, 2020 by Noel_Flantier Quote Link to comment Share on other sites More sharing options...
Solution OxyGenS Posted December 17, 2019 Solution Share Posted December 17, 2019 Attention, c'est 1/Vmax qui augmente donc Vmax diminue Quote Link to comment Share on other sites More sharing options...
Ancien Responsable Matière Noel_Flantier Posted December 17, 2019 Author Ancien Responsable Matière Share Posted December 17, 2019 @OxyGenS merci beaucoup ! Quote Link to comment Share on other sites More sharing options...
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