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ccb 2019


pacesenY
Go to solution Solved by Jadilie,

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  • Ancien Responsable Matière
  • Solution

∆E' = ∆E0' - 0,06/n * log (succinate/FAD) -  pH*0,06*x/n, avec x le nombre de H+ échangés

∆E = ∆E0      ''                             ''                      sans ce terme.

Ce n'est pas une réaction acide base, donc aucune H+ n'est échangé, x=0, donc ∆E0=∆E0'

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