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CC 2015 PURPAN


pastèque
Go to solution Solved by Lénouillette,

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  • Ancien Responsable Matière
  • Solution

C'est parce que tu as cos(2x) et pas cos(x), du coup comme tu as le facteur multiplicateur devant, si tu considères f(x+k\pi ), tu vas avoir cos(2(x+k\pi )), ce qui fait cos(2x+2k\pi), ça correspond bien à la périodicité de la fonction cosinus ?

Edited by lenouillette
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