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célérité, fréquence, énergie


NomdeZeus
Go to solution Solved by Gabin,

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Salut,

 

Alors on commence par l'item A : une onde qui se propage dans le vide c'est une OEM, elle va donc à la vitesse de la lumière (300 000 km/s).

 

Item B \lambda = \frac{c}{f} \Rightarrow f = \frac{c}{\lambda } = \frac{3.10^{8}}{50.10^{-3}}=\frac{3}{5}.10^{10}=6.10^{9} Hz 

Item C E = h.\nu = 6,626.10^{-34} \times 6.10^{9} = (6,626 \times 6).10^{-25}=39,756.10^{-25}J\approx 4.10^{-24}J

 

J'espère que ça t'aidera!!

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