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QCM 18 CC 2015


Go to solution Solved by sskméta,

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Posted

Salut, je m'essaye :

 

le temps mort, le temps perdu entre chaque mesure vaut 0,1 ms (= 0,1 x 10^(-3) secondes) - tu as 2000 mesures/s ducoup pour ces 2000 interractions tu vas perdre 2000 x 0,1 x 10^(-3) secondes = 0,2 secondes

 

 

Pense à mettre utiliser la fonction "meilleure réponse"  ;)

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