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test diag


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Bonjour,

Pour répondre à cette question on utilise la formule suivante: image.thumb.png.7e7e5811dee74da65b27a7c0eaa46da6.png

Avec Se= 90/100 et Spe= 200/300 et p=10/100.

 

On obtient: image.thumb.png.b2eb2cd687c332ee30130b49dd4cd856.png

 

Donc l'item E est bien vrai.

J'ai essayé de bien détailler les calculs pour que ça soit compréhensible...

 

Bonne journée!

 

 

 

 

 

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