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differentiation logq


Go to solution Solved by RaphaelAustry,

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Posted

tu commences par appliquer le logarithme sur V, ça te donne log(V)= log4/3 + logPi + logR3

ensuite, si tu dérives, log 4/3 et logPi s'annulent, il te reste log(R3)', hors log(R3)= 3log®, donc:

d(V)/V=3/R*dR

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