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QCM 3 pharma pack poly


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Posted (edited)

En faite si c'est la même chose. si tu reprends ton cours à la diapo 12 tout en bas il y a une égalité qui dit que à T1/2 On a [A]0-[A]=[A]0-([A]0/2)=[A]0/2 ce qui donne la formule finale de T1/2=[A]0/2*k=([A]0/2)*(1/k) donc tu peux remplacer ton [A]0/2 par [A]0-[A]. C'est la même chose.

N'hésite pas si c'est toujours pas clair.

 

Edited by PASSlesrep

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