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biophysique purpan 2019 2020 qcm 6


Go to solution Solved by Cool-idge,

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Salut, 

 

Alors la D, alpha c'est 4/2 et le  neutron c'est 1/0, tu vérifies 122 + 4 = 126 et 123 + 3x1 = 126 on est bon, maintenant dans ton tableau en début d'énoncé, tu dois regarder si le Xe peut se transformer en I, en fonction de leur énergie de masse respective, l'I devant avoir une énergie de masse plus faible. 

 

C'est ok ? 

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