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intervalle de confiance


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Posted (edited)

om84.png

la formule est la suivante IC = [m - 2 \times \frac{\sigma}{\sqrt{N}} ; m + 2 \times \frac{\sigma}{\sqrt{N}}]

Dans ton cas IC = =[72 - 2 \times \frac{9}{\sqrt{100}} ; 72 + 2 \times \frac{9}{\sqrt{100}}] \\ = [72 - 2 \times \frac{9}{10} ; 72 + 2 \times \frac{9}{10}] \\ = [72 - 1,8 ; 72 + 1,8] = [70,2 ; 73,8]

l'item est juste

Pour ceux que ça intéresse je met le code LaTeX :

IC = [ m - 2 \times \frac{\sigma}{N} ;  m + 2 \times \frac{\sigma}{N} ]

vous le collez dans formule et ça donne ça gif.latex?IC%20%3D%20%5B%20m%20-%202%20%

@tellierclementine

Edited by Dr_Zaius

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