V16 Posted January 10, 2021 Posted January 10, 2021 Bonjour! je ne comprends pas d'où sort le 0,52 (dans 0,48P-0,52 ) et le -1,13 (dans 0,13A^-1,13) dans la différencielle Quote
Solution Chat_du_Cheshire Posted January 10, 2021 Solution Posted January 10, 2021 hello c'est la formule de la dérivée : (x^n)' = nx^n-1 Si n = 0,48, ça donne un exposant égal à n-1 = 0,48-1 = -0,52 (idem pour -1,13, -0,13-1 = -1,13) Quote
V16 Posted January 10, 2021 Author Posted January 10, 2021 Ah mais oui je suis bête! merciii Chat_du_Cheshire 1 Quote
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