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QCM DO optique


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Salut !

 

Si, comme le dit l'item D, on a bien 90% d'oxyhémoglobine dans la solution, on a 10% d' Hb réduite.

Donc DO à 780nm =  0,9x1050 + 0,1x700 = 0,9x3x350 + 0,1x2x350 = 2,7x350 + 0,2x350 = 350x(2,7+0,2) = 350x2,9.

Et DO à 940nm =  0,9x700 + 0,1x1050 =0,9x2x350 + 0,1x3x350 = 1,8x350 + 0,3x350 = 350x(1,8+0,3) = 350x2,1.

Donc si on reprend les données de l'item : DO à 780nm/DO à 940nm = 350x2,9/350x2,1 = 2,9/2,1 = 29/21. 

 

Donc l'item D est VRAI, et par conséquent l'item E est FAUX.

 

J'espère que j'ai pu t'aider !

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