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enzymo​😅​


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  • Ancien Responsable Matière
Posted

bonjour, 

 

quel calcul faut-il faire pour répondre a cet item svp

Lors d’une cinétique michaélienne, si la concentration en substrat est égale à 1/2 Km et s’il y a un inhibiteur de type compétitif dont la concentration est équivalente à 10-4 Km, la vitesse initiale de la réaction sera proche de :

 

A. 0,125 Vmax. B. 0,33 Vmax. C. 0,500 Vmax. D. 0,66 Vmax. E. 0,98 Vmax.

 

merci d'avance 🙂

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