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CCB M2020


Go to solution Solved by Skinfaxiii,

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Posted

Coucou, 

Si la piste B contient la tutorine, ça ne peut pas être un protéine homodimérique (deux sous unité identique) car on nous dit dans l'énoncé que sa masse moléculaire est 108 kDa, or là on a une bande qui est environ à 110 kDa donc si elle était vraiment homodimerique ca dépasserait largement 108 kDa. 

 

 

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