Jump to content

td chimie


Go to solution Solved by SBY,

Recommended Posts

  • Ancien Responsable Matière
  • Solution
Posted (edited)

Salut @NGN3701A

Dans l'item 7D, on trouvait que ΔG°'1= ΔG°'3 - 2 ΔG°'2

Or, ΔG°'=-RTLnK

Donc : -RTlnK'1 = -RTlnK'3+ 2RTlnk'2

          <=>   lnK'1 = lnK'3- 2 lnk'2

          <=>   lnk'1 = lnK'3 - ln(k'2)2

          <=>   lnk'1 = lnk'3 / ln(k'2)2

          <=>   k'1 = k'3 / (k'2)2

J'espère que c'est plus clair pour toi. 

Bonne journée ! 

Edited by SBY

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...