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Oxydo/réduction n.o.


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Posted

Salut ! Dans un qcm, on demande quel est le no du N dans H2N-NH2 et dans N2O3 

j'ai bien compris le concept pour trouver les no mais là je bloque (il n'y a pas de correction) si qqn peut m'aider 🙂 

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Posted

Hey 😉

 

- H2N-NH2 peut également s'écrire N2H4 :

 

2 x no(N) + 4 x no(H) = 0 avec no(H) = 1

2 x no(N)  + 4 x 1 = 0

2 x no(N) = -4

no(N) = -2

 

- N2O3:

 

2 x no(N) + 3 x no(O) = 0 avec no(O) = -2

2 x no(N) + 3 x (-2) = 0

2 x no(N) - 6 = 0

2 x no(N) = 6

no(N) = 3

 

Est-ce que c'est plus clair ?

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