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Salutation, je ne comprends pas la correction de l'item E du qcm 103, pourquoi le NH2 reste sur la molécule ? Alors qu'il devrait partir pour former Net H2O  laissant sur la molécule un alcool, comme dans le QCM 107 du TAT. Parce que dans la correction E du 103 le NH reste sur la molécule et il y a donc un N en trop dans la réaction non ?

Merci d'avance ! 

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