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QCM 54 lipides entrainement


Go to solution Solved by ValentineMartel,

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Posted

Salut, 

 

Pour le C, c'est parce que l'AA en position 1 est lié par une liaison alkyl et non acyl donc c'est insensible à la PLA1. Et la seconde molécule n'est pas un phospholipide donc pareil, la PLA1 n'agit pas. 

Pour la D, le produit libéré ne sera pas 1-palmitoyl mais 1-hexadecyl, la liaison n'a pas changé 😉 

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