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QCM 5 cc2010 (TD1)


Go to solution Solved by Soleneuh,

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Posted

Bonjours,

Je ne comprends pas comment répondre à la D comme on ne nous donne pas le coef de dissociation de l'antibiotique.

Sachant que : m(antibio)=0.02; m(Na2SO4)=0.1 ; et i(NaSo4)=2.8 

1570607733-qcm-2010-5.png

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Posted (edited)

Salut !

Pars du principe que là le coef de dissociation est de 0 (on te le donne pas et en plus antibiotique va pas se dissocier), donc quand tu vas calculer le i de ton antibiotique --> i= 1+ alpha(p-1) et du coup pour l'osmolarité de antibiotique tu fais comme si i=1 (car alpha =0)

C'est mieux pour toi ?

Edited by Soleneuh

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