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Variation d'énergie


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Bonjour, dans la formule la variation d'énergie d'un faisceau en RIM dR=N.dE+E.dN , est-ce que quelqu'un peut m'indiquer la signification du d de dR, dE et dN.

Merci.

  • Solution
Posted (edited)

C'est la variation ! Puisque l'énergie du faisceau peut varier 🙂

A noter que NdE = 0 dans le cas des photons puisqu'ils disparaissent après interaction avec la matière !

Edited by Chat_du_Cheshire

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