Jump to content

CC P2013 qcm6


Go to solution Solved by Cléclé8,

Recommended Posts

  • Solution
Posted

Salut je pense que tu as oublier de mettre 0,1 au carré -> Car dans la formule on a v2/c2 = (0,1 c)^2 / c^2 = 0,01 c^2. 

Donc 1+ 0,5 x 0,01 -1 =0,005

0,005 x 0,511 = 0,002555 MeV = 2,5 keV

 

Tu as compris ?

 

  • Ancien Responsable Matière
Posted

@SoM n'hésite pas à mettre le sujet en résolu si tu penses qu'on a répondu à ta question 😉 

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...