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CC purpan 2018 maths


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Posted

Bonjour! Sur l'annale 2017/2018 de purpan qcm 3 itdem D, je ne comprend pas pourquoi elle est vraie. Quelqu'un pourrait m'expliquer stp?

Screenshot 2019-01-14 at 15.55.21.png

  • Solution
Posted

Salut!

Si on impose y = x alors la fonction f(x,y) devient:

f(x,x) = \frac{xx}{x^2+x^2} = \frac{x^2}{2(x^2)} = \frac{1}{2}

Donc cette fonction ne dépend pas de x 

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