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Annale 2015/2016 purpan UE3bis


Go to solution Solved by LénaEsn,

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Posted (edited)

Salut !

Alors dans ton cours tu as cette formule pour un liquide réel newtonien : v(moy) = D/(π*r²).

Ici D = 1L/min, ça équivaut à 1*10^-3 m^3/min, et la section, donc (π*r²) = 10 cm² soit 10*10^-4 m² (on souhaite avoir la même unité).

Du coup tu as : v(moy) = 1*10^-3/10*10^-4 = 1m/min (fais le calcul des unités pour vérifier de bien tomber sur des m/min).

Voilà le calcul à faire, j'espère que c'est clair :) bon courage !

 

 

Edited by LénaEsn
Erreur de calcul

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