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QCM 24 R-2013


Go to solution Solved by La_Reine_Rouge,

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Posted

Salut salut, si quelqu'un peut m'expliquer ce QCM, dont je ne comprends pas du tout la correction.. Merci ;)

 

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  • Solution
Posted

Bonjour,

 

Tu sais que Emittance énergétique (ou luminance) est proportionnelle à la T^4.

Si T est multiplié par 2, alors emittance et luminance sont multipliés par 2^4 = 16 :)

Donc A faux, B et C vrais.

Ensuire Lambda(max) = constante / T, donc si tu as 2*T tu divises lambda par 2 donc D faux.

Et E faux c'est ortho ;)

 

Dac ?

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