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qcm 9 CC 2012


Go to solution Solved by VM-Varga,

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Posted

Bonjour !

 

Ton erreur se trouve au niveau des unités. En effet lambda doit être en secondes-1, il faut donc diviser lambda par soixante pour harmoniser les unités.

==> 6,3.10-3 divisé par 60 donne 0,105.10-3

 

Ainsi avec la formule A= lambda x N, on retombe bien sur l'item B.

 

En espérant t'avoir éclairé :)

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