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Posted
4 minutes ago, Batman_sans_Robin said:

Bien le bonjour à vous,

 

https://zupimages.net/viewer.php?id=25/11/qcyv.jpeg Par quel calcul peut-on trouver la réponse E ? 

 

Bien à vous, Batman (:

Salut,

par aucun calcul juste les coeff stochiometriques. Le coeff stoechio c'est combien de moles de chaque espece reagissent pour en former combien d'autres. Ainsi, 3BrO- = BrO3- + 2Br- veut dire que 3 moles de BrO- forment 1 mole de BrO3- et 2 moles de Br- . Ainsi, 0,3 moles de BrO- forment 0,1 mole de BrO3- et 0,2 moles de Br- (on divise tous les coeff par 10).

Avec plaisir !

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