Jump to content

QCM entrainement 14D


Go to solution Solved by bêta-arezkin,

Recommended Posts

Posted

bonjour (encore....),

Je ne comprend pas la correction du QCM14D 

on a un schéma avec des courbes et en ordonné on a 1/V, la courbe X2 passe a 1/V=3 donc V = 0,3 et la courbe X1=1/V=2 donc V= 0,5.

J'en conclus que V(X1)>V(X2) 

correction : FAUX "Attention à bien lire les valeurs, ici on a en ordonnées 1/V et non pas V donc c’est l’inverse"

Je ne comprend donc pas..

merci

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...