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S2 2020-2021 cinétique


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Posted

Salut,

tu sais que t 1/2 = ln2/k 

et pour avoir t 1/10 tu fais 5 x t 1/2 (car 1/2 = 5 x 1/10)

donc, t 1/10 = 5 x ln2/k = ln10/k (car 5ln2 = ln10)

j'espère que c'est plus clair pour toi

 

Posted
il y a 46 minutes, ilhamoxiciIline a dit :

Salut,

tu sais que t 1/2 = ln2/k 

et pour avoir t 1/10 tu fais 5 x t 1/2 (car 1/2 = 5 x 1/10)

donc, t 1/10 = 5 x ln2/k = ln10/k (car 5ln2 = ln10)

j'espère que c'est plus clair pour toi

 

Super explications!! ;)

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